tan(π/4+α) - tan(π/4-α) =tan((π/4+α)-(π/4-α))[1+(tan(π/4+α)tan(π/4-α)]
=tan2α[1+(tan(π/4+α)tan(π/4-α)]
所以,[ tan(π/4+α) - tan(π/4-α) ] / tan2α - tan(π/4+α)tan(π/4-α)
=1
化简：[ tan(π/4+α) - tan(π/4-α) ] / tan2α - tan(π/4+α)tan(π/4-α
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