Question

y=x/4^x y=(1-lnx)/(1+lnx) y=sin^4 x/4+cosx/4 计算导数!

Answer 1

(1)y=x/4^x

y'=[x'(4^x)-x(4^x)']/4^2x

=(1-x▪ln4)/(4^x)

(2) y=(1-lnx)/(1+lnx)

y'=[(1-lnx)'(1+lnx)-(1-lnx)(1+lnx)']/(1+lnx)²

=(lnx-1)/[x(1+lnx)]

(3)y=sin^4 x/4+cosx/4

y'=sinx^3▪cosx-sinx/16