Question

解方程组{█(x=(3y+1)/2@(y+1)/4=(x+2)/3)┤

Answer 1

x=(3y+1)/2

代入

3(y+1)=4(x+2)

3y+3=4x+8

所以3y+3=4(3y+1)/2+8

3y+3=6y+2+8

3y=-7

y=-7/3

x=(3y+1)/2=-3