f(x) = 2sin^2(x+π/4) - √ 3cos2x
= - [1-2^2(x+π/4)] - √ 3cos2x + 1
= - cos(2x+π/2) - √ 3cos2x + 1
= sin2x - √ 3cos2x + 1
= 2sin(2x-π-3) + 1
因为 |f(x)-m| -3,2-m
f(x) = 2sin^2(x+π/4) - √ 3cos2x
= - [1-2^2(x+π/4)] - √ 3cos2x + 1
= - cos(2x+π/2) - √ 3cos2x + 1
= sin2x - √ 3cos2x + 1
= 2sin(2x-π-3) + 1
因为 |f(x)-m| -3,2-m