f(x)=√3sin2x+cos2x
=2sin(2x+π/6)
g(x)=2sin(4x+5π/6)
x∈[0,π/8]
则:4x+5π/6∈[5π/6,4π/3]
则:sin(4x+5π/6)∈[-√3/2,1/2]
所以:g(x)∈[-√3,1]
即g(x)在区间[0,π/8]上的最小值为-√3
缩短后为2sin(4x+π/6)
左移后为2sin(4(x+π/6)+π/6)=2sin(4x+4π/6+π/6)=2sin(4x+5π/6)
f(x)=√3sin2x+cos2x
=2sin(2x+π/6)
g(x)=2sin(4x+5π/6)
x∈[0,π/8]
则:4x+5π/6∈[5π/6,4π/3]
则:sin(4x+5π/6)∈[-√3/2,1/2]
所以:g(x)∈[-√3,1]
即g(x)在区间[0,π/8]上的最小值为-√3
缩短后为2sin(4x+π/6)
左移后为2sin(4(x+π/6)+π/6)=2sin(4x+4π/6+π/6)=2sin(4x+5π/6)