Question

dx/(根号下1-2x）的积分得多少

Answer 1

原式=-1/2*∫f(-2x)/√(1-2x)

=-1/2*∫(1-2x)^(1/2)f(1-2x)

=(-1/2)*[(1-2x)^(1/2+1)]/(1/2+1)+C

=-(1/3)*[(1-2x)^(3/2)]+C

=-1/[3(1-2x)√(1-2x)]+C