Question

计算题（整式)(X+3).(X+4)=(Y-1).(Y-2)=(Y+2).(Y-2)=(2A-1).(3A-2)=(2A

Answer 1

(X+3).(X+4)= X^2+7X+12

(Y-1).(Y-2)= Y^2-3Y+2

(Y+2).(Y-2)= Y^2-4

(2A-1).(3A-2)= 6A^2-7A+2

(2A+3).(3A-2)= 6A^2+5A-6

(3X-5Y).(2X+3Y)= 6X^2-XY-15Y^2

(A+B-C).(A-B-C)= A^2-B^2+C^2-2AC

(2X-3Y-Z).(2X-3Y+Z)=4X^2+9Y^2-Z^2-12XY