f(x)=√3sinxcosx-cos²x-1/2
= √3/2(2sinxcosx)-1/2(1+cos2x)-1/2
=√3/2sin2x-1/2cos2x-1
=sin2xcosπ/6-cos2xsinπ/6-1
=sin(2x-π/6)-1
哪里看不懂?
老师这题求详解!我数学底子差 看不懂是怎么变式的
f(x)=√3sinxcosx-cos²x-1/2
= √3/2(2sinxcosx)-1/2(1+cos2x)-1/2
=√3/2sin2x-1/2cos2x-1
=sin2xcosπ/6-cos2xsinπ/6-1
=sin(2x-π/6)-1
哪里看不懂?