Question

5/x+1 -4/y-2=2 7/x+1 +3/2-y=13/20 请用换元法解这道二元一次方程组

Answer 1

s=1/(x+1) t=1/(y-2)

5s-4t=2

7s-3t=13/20

(28-15)s=13/5-6

s=-17/65

(-15+28)t=-43/4

t=-43/52

x+1=-65/17 x=-82/17

y-2=-52/43 y=34/43