Question

（3x＋2y－5）²与丨5x＋3y－8丨互为相反数,x等于几 y等于几

Answer 1

（3x＋2y－5）²与丨5x＋3y－8丨互为相反数,

则（3x＋2y－5）²+丨5x＋3y－8丨=0

因为（3x＋2y－5）²≥0,丨5x＋3y－8丨≥0

所以3x+2y-5=0,①

5x+3y-8=0②

①×3-②×2,得9x-15-10x+16=0,解得x=1

代入①,解得y=1