Question

求道积分函数题∫x/[(x^2+1)^(1/2)]dx 怎么变成 (x^2+1)^(1/2) 法海，错怪你了

Answer 1

∫x/[(x^2+1)^(1/2)]dx

=1/2*∫[1/√(x^2+1)]d(x²+1)

=∫[1/(2√(x^2+1))]d(x²+1)

=√(x²+1)+C