Question

p*根号下1-p^2的原函数是什么

Answer 1

∫p√(1-p²)dp

=-1/2∫(1-p²)^(1/2)d(1-p²)

=-1/2*(1-p²)^(1/2+1)/(1/2+1)+C

=-(1-p²)√(1-p²)/3+C