Question

(a-b-c)(a+b-c)+(b-c-a)(b+c-a)a^4-81m^2(a+b)-4(a+b)m^2(p-q)-p

Answer 1

(1)原式=(a-b-c)(a+b-c)-（b-c-a）(a-b-c)

=(a-b-c)(a+b-c-b+c+a)

=2a(a-b-c)

(2)原式=(a^2)^2-9^2

=(a^2-9)(a^2+9)

=(a^2+9)(a+3)(a-3)

(3)原式=m^2(p-q)-(p-q)

=(m^2-1)(p-q)

=(m+1)(m-1)(p-q)

(4)原式=(2x^2+4x)^2-2^2

=(2x^2+4x-2)(2x^2+4x+2)

=4(x^2+2x-1)(x+1)^2

解答题：

∵a^2+2ab+b^2=0,∴（a+b）^2=0

∴a=-b

∴原式=-b(-b+4b)-(-b+2b)(-b-2b)

=0

打得我手痛了,采纳吧.