两条直线L1:(m+3)x+2y=5-3m,L2:4x+(5+m)y=16,当L1与L2垂直时M为何值?
1个回答
[-(m+3)/2]*[-4/(5+m)]=-1,且(m+3)(5+m)≠0
2(m+3)/(5+m)=-1
2m+6+m+5=0
m=-11/3
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