lim(h>0)[f(x0)-f(x0-2h)]/h
=lim(h>0) 2* [f(x0)-f(x0-2h)]/2h
=2*lim(h>0) [f(x0)-f(x0-2h)]/2h
=2f'(x0)
设函数f(x)在x=x0处可导,则lim(h>0)[f(x0)-f(x0-2h)]/h
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