设直线为截距式x/a+y/b=1,
依题意得2/a+1/b=1……①,|ab|=8,
⑴当ab=8时,与①联立方程组,
解之得,a=4,b=2;
∴直线方程是 :x/4+y/2=1.
⑵当ab=﹣8时,与①联立方程组,
解之得,a=4﹙√2-1﹚,b=﹣2﹙√2+1﹚或
a′=﹣4﹙√2+1﹚,b′=2﹙√2-1﹚;
∴直线方程是:
x/4﹙4√2-1﹚-y/2﹙√2+1﹚或
﹣x/4﹙√2+1﹚+y/2﹙√2-1﹚.
设直线为截距式x/a+y/b=1,
依题意得2/a+1/b=1……①,|ab|=8,
⑴当ab=8时,与①联立方程组,
解之得,a=4,b=2;
∴直线方程是 :x/4+y/2=1.
⑵当ab=﹣8时,与①联立方程组,
解之得,a=4﹙√2-1﹚,b=﹣2﹙√2+1﹚或
a′=﹣4﹙√2+1﹚,b′=2﹙√2-1﹚;
∴直线方程是:
x/4﹙4√2-1﹚-y/2﹙√2+1﹚或
﹣x/4﹙√2+1﹚+y/2﹙√2-1﹚.