Question

x^2(y+z)^2-2xy(x-z)(y+z)+y^2(x-z)^2 =[x(y+z)-y(x-z)]^2 =(xz+

Answer 1

x²(y+z)²-2xy(x-z)(y+z)+y²(x-z)² 完全平方式分解因式

[x(y+z)]²-2×x(y+z)×y(x-z)+[y(x-z)]²

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a² -2 a b + b² =(a+b)²

=[x(y+z)-y(x-z)]² 去掉里面的括号,并合并同类项

xy+xz-xy+yz=xz+yz

=(xz+yz)² 提取公因式 [z(x+y)]²

=z²(x+y)² 公式(ab)^n=a^nb^n