Question

急,一道关于log的高中数学题!

Answer 1

log(12,27)=3log(12,3)=a∴ log(12,3)=a/3

log(6,16)=2log(6,4)=2[log(12,4)]/log(12,6)=2[log(12,12/4)]/[log(12,√36)]

=2[log(12,12)-log(12,3)]/[1/2log(12,12×3)]=[2(1-a/3)]/[1/2(1+a/3)]

=[4(3-a)]/(3+a)