sin(α+3π)+cos(π+α)/sin(－α)-cos(π+α)
=-sin(α)-cos(α) / -sin(α)+cos(α)
= -tan(α)-1 / -tan(α)+1
=(-m-1)/(-m+1)
=(m+1)/(m-1)
tanα=m,则sin(α+3π)+cos(π+α)/sin(－α)-cos(π+α)等于?
1个回答
相关问题
-
设tan（π+α）=2，则sin(α−π)+cos(π−α)sin(π+α)−cos(π+α)=（ ）
-
若tan(7π+α)=a,则sin(α-3π)+cos(π-α)/sin(-α)-cos(π+α)=?
-
设tan（5π+α）=m，则sin(α−3π)+cos(π−α)sin(−α)−cos(π+α)的值为 ______．
-
..sin^2（π+α）*cos（π+α）*cos（-α-2π）/tan（π+α）*sin^3（π/2+α）*sin（-
-
化简：（Ⅰ）sin(α−2π)cos(α+π)tan(α−99π)cos(π−α)sin(3π−α)sin(−α−π)；
-
tan(π+α)=3 则 sin(π+α)cos(π-α)=?
-
f(α)=sin(π-α)*cos(2π-α)/sin(3π/2-α)tanα,则f(-10π/3)等于
-
化简：sin(3π+α)•cos(π−α)•tan(3π2+α)cos(π3)•sin(π2−α)•cos(−α)=__
-
已知tanα=2,sinα+cosα＜0,求[sin(2π-α)*sin(π+α)*cos(-π+α)]/[sin(3π
-
若tan(7π+α)=α,求sin(α+3π)+cos(π-α)/sin(-α)-cos(π+α)的值