额,这个你只要记住算法就行了.设x的系数为w,用2π/w.就行了
y=2sin三分之一x y=4sin(x-π/3) y=sin(2x+π/6) y=3sin(1/2x-π/4) 的周期
2个回答
相关问题
-
y=|sin(2x+π/4)|的周期为π/2,而y=|sin(2x+π/4)+1/2|的周期为π
-
y=sin(π/4+x/2)sin(π/4-x/2) =sin(π/4+x/2)sin[π/2-(π/4+x/2)]
-
求下列函数的周期(1)y=2sin1/2x (2)y=cos(x+π/3) (3)y=2sin(2/3x-π/4)
-
y=3sin(2x+π/4)=3sin[2(x+π/8)] 为什么
-
1.y=cos^4x+sin^4x 求周期 2.y=(sin2x+sin(2x+π/3))/( cos2x+cos(2x
-
y=sin(x+π/6)如何移动得到y=sin(2x+π/3)
-
求值域 (1)y=2sin(x/2+π/4)x∈[0,π) (2)y=2cosx-sin^2x+3 x∈[-π/3,2/
-
y=3sin(2x+π/5)怎么变化得到y=2sin(2x+π/4)
-
求函数y=[sin2x+sin(2x+π/3)-cos1/2﹙π-4x﹚]/[cos2x+cos﹙2x+π/3﹚-sin
-
求下列函数定义域1.y=3cosx2.y=-cosx3.y=sin(x+π/4)4.y=sin[(π/4)-x]= =