sin(π/4+x/2)sin(π/4-x/2) =sin(π/4+x/2)sin[π/2-(π/4+x/2)]∵π/4=π/2-π/4∴sin(π/4-x/2) =sin(π/2-π/4-x)=sin[π/2-(π/4+x/2)]这里还没有公式呢?下面sin[π/2-(π/4+x/2)]=cos(π/4+x/2) 【sin(...
y=sin(π/4+x/2)sin(π/4-x/2) =sin(π/4+x/2)sin[π/2-(π/4+x/2)]
1个回答
相关问题
-
2sin(x+π/4)sin(x-π/4)=?
-
2sin（πx/4-π/4）+6＜2sin（πx/4-3π/4）+8
-
求证:sin(π/4+x)/sin(π/4-x)+cos(π/4+x)/(π/4-x)=2/cos2x
-
f(x)=（1+cotx)sin^2x-2sin(x+π/4)sin(x-π/4)
-
sin(2x+π/4)怎样变成sin(x+π/2)
-
y=sinx+cosx可化成_____?A.2sin(x-π/4)；B.2sin(x+π/4)； C.√2sin(x-π
-
sin(x-π/4 + π/2 )=-cos(x+π/4)
-
函数f(x)=2sin(x+π/4)sin(x-π/4)+sin2x的值域
-
f(x)=1-2sin^2(x+π/8)+2sin(x+π/8)*cos(x+π/8)=cos(2x+π/4)+sin(
-
y=|sin(2x+π/4)|的周期为π/2,而y=|sin(2x+π/4)+1/2|的周期为π