sin(180°+α)+cos(90°+α)= -α
-sinα-sinα=-α
sinα=α/2
cos(270°-α)+2sin(360°-α)
= cos(180+90-α)-2sinα
=-sinα-2sinα
=-3sinα = (-3/2)α
选B
sin(180°+α)+cos(90°+α)= -α
-sinα-sinα=-α
sinα=α/2
cos(270°-α)+2sin(360°-α)
= cos(180+90-α)-2sinα
=-sinα-2sinα
=-3sinα = (-3/2)α
选B