f(x) = √3 sin2x+2cos²x+m=√3 sin2x+1+cos2x+m=2sin(2x+π/6)+m+1,
当2x+π/6=π/2,x=π/6时,f(x)取最大值,m+3=6,m=3.
当x 属于R时,f(x)的最小值为4,此时2x+π/6=2kπ+π,k为自然数,x=kπ+5π/12.
答:m=3.当X属于R时的最小值为4,取最小值时X的集合为x=kπ+5π/12.
f(x) = √3 sin2x+2cos²x+m=√3 sin2x+1+cos2x+m=2sin(2x+π/6)+m+1,
当2x+π/6=π/2,x=π/6时,f(x)取最大值,m+3=6,m=3.
当x 属于R时,f(x)的最小值为4,此时2x+π/6=2kπ+π,k为自然数,x=kπ+5π/12.
答:m=3.当X属于R时的最小值为4,取最小值时X的集合为x=kπ+5π/12.