1、if sinx-siny= -1/3,cosx-cosy=1/2,then cos(x-y)=?

1个回答

  • 1、cosx-cosy=1/2 ,sinx-siny=-1/3

    分别两边平方

    (cosx)^2-2cosxcosy+(cosy)^2=1/4

    (sinx)^2-2sinxsiny+(siny)^2=1/9

    相加

    且(cosx)^2+(sinx)^2=1 (cosy)^2+(siny)^2=1

    2-2(cosxcosy+sinxsiny)=1/4+1/9=13/36

    cos(x-y)=cosxcosy+sinxsiny

    =(2-13/36)/2

    =59/72

    2、sinπ/14 sin3π/14 sin5π/14

    = cos6π/14 cos4π/14 cos2π/14

    =cosπ/7 cos2π/7 cos3π/7……(1)

    因2sinθcosθ=sin2θ

    又sin3π/7=sin4π/7sin6π/7=sinπ/7

    所 (1)*sinπ/7= sinπ/7 cosπ/7 cos2π/7 cos3π/7

    =1/2 sin2π/7 cos2π/7 cos3π/7

    =1/4 sin4π/7 cos3π/7

    =1/4 sin3π/7 cos3π/7

    =1/8 sin6π/7

    =1/8 sinπ/7

    而(1)*sinπ/7=1/8 sinπ/7

    所(1)式=1/8

    3、tan60=tan(20+40)=(tan20+tan40)/(1-tan20tan40)

    tan20+tan40=tan60(1-tan20tan40)

    (tan20+tan40+tan120)/tan20*tan40

    =[tan60(1-tan20tan40)-tan60]/(tan20*tan40)

    =-(tan60tan20tan40)/(tan20*tan40)

    =-tan60

    =-√3

    终于做完了,手好酸啊