设a不等于b,m不等于n,a、b、m、n是已知数,则方程组 {x/(a+m)+y/(b+m)=1 x/(a+n)+y/(

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  • x/(a+m)+y/(b+m)=1

    x/(a+n)+y/(b+n)=1

    x/(a+m)+y/(b+m)=1 .x(b+m)+y(a+m)=(b+m)(a+m).x+y(a+m)/(b+m)=(a+m)

    x/(a+n)+y/(b+n)=1 .x(b+n)+y(a+n)=(b+n)(a+n).x+y(a+n)/(b+n)=(a+n)

    y(a+m)/(b+m)-y(a+n)/(b+n)=(a+m)-(a+n)

    y[(a+m)/(b+m)-(a+n)/(b+n)]=(m-n)

    y[(a+m)(b+n)-(a+n)(b+m)]/[(b+n)(b+m)]=(m-n)

    y[(ab+bm+an+mn)-(ab+bn+am+mn)]/[(b+n)(b+m)]=(m-n)

    y[bm+an-bn-am]/[(b+n)(b+m)]=(m-n)

    y[(bm-am)+(an-bn)]/[(b+n)(b+m)]=(m-n)

    y[m(b-a)+n(a-b)]/[(b+n)(b+m)]=(m-n)

    y[(b-a)(m-n)]/[(b+n)(b+m)]=(m-n)

    y(b-a)=[(b+n)(b+m)]

    y=[(b+n)(b+m)]/(b-a)

    x/(a+m)+y/(b+m)=1

    x/(a+m)+{[(b+n)(b+m)]/(b-a)}/(b+m)=1

    x/(a+m)+[(b+n)(b+m)]/[(b-a)(b+m)]=1

    x/(a+m)=1 -[(b+n)(b+m)]/[(b-a)(b+m)]

    x/(a+m)={[(b-a)(b+m)] -[(b+n)(b+m)]}/[(b-a)(b+m)]

    x/(a+m)={(b+m)(b-a -b-n)}/[(b-a)(b+m)]

    x/(a+m)=(-a -n)/(b-a)

    x/(a+m)=(a+n)/(a-b)

    x= [(a+m)(a+n)]/(a-b)

    x= [(a+m)(a+n)]/(a-b)

    y=[(b+n)(b+m)]/(b-a)