(1)f(x)=根号3sin(wx+φ)-cos(wx+φ)=2Sin(wx+φ-π/6)
由于是偶函数,即f(x)=f(-x）
即2Sin(wx+φ-π/6)=2Sin(-wx+φ-π/6)
即SinwxCos(φ-π/6)+CoswxSin(φ-π/6)=-SinwxCos(φ-π/6)+CoswxSin(φ-π/6)
即SinwxCos(φ-π/6)=0
又Sinwx不恒等于0,所以Cos(φ-π/6)=0
又0
[非常急]已知函数f(x)=根号3sin(wx+φ)-cos(wx+φ)(0
4个回答
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