Question

设x=1+t^2、y=cost 求 dy/dx 和d^2y/dx^2 sint-tcost/4t^3 和 sint-tc

Answer 1

∵x=1+t²,y=cost

==>dx/dt=2t,dy/dt=-sint

∴d²y/dx²=d(dy/dx)/dx

=(d((dy/dt)/(dx/dt))/dt)/(dx/dt)

=(d((-sint)/(2t))/dt)/(2t)

=((sint-tcost)/(2t²))/(2t)

=(sint-tcost)/(4t³)

故(sint-tcost)/(4t³)才是对的.