设{x=sint y=cos2t,则dy/dx|t=π/4=
1个回答
dx/dt=cost=√2/2
dy/dt=-2sin2t=-2
所以dy/dx|t=π/4=dy/dt÷dx/dt=-2√2
相关问题
x=sint+1 y=2cos3t dy/dx
设x=1+t^2、y=cost 求 dy/dx 和d^2y/dx^2 sint-tcost/4t^3 和 sint-tc
设x=sint,y=cost则dy/dx=
x=2t^2 +1 y= sint 求dy/dx是多少?
设x=e'sin t,y=e'cos t,求dy/dx.
已知{x=sint^2 y=(2t+5)^2 求dy/dx
设x=e^-t y=e^-2t 求dy/dx
设f(x)=∫(0,π)sint/(π-t)dt,求∫(0,π)f(x)dx
设x=3e^-t,y=2e^t,则dy/dx等于多少?
设y=yx,x=sint ,y=arctant,求dy/dx