(1+2+3+...+9+10+9+...+3+2+1)/(2^2+4^2+...+100^2-1^2-3^2-99^2)
=((1+9)*9+10)/(2^2-1^2+4^2-3^2+...+100^2-99^2)
=100/(3+7+11+...+199)
=100/5050
=2/101
(1+2+3+...+9+10+9+...+3+2+1)/(2^2+4^2+...+100^2-1^2-3^2-99^2)
=((1+9)*9+10)/(2^2-1^2+4^2-3^2+...+100^2-99^2)
=100/(3+7+11+...+199)
=100/5050
=2/101