Question

解方程 1. 4(x+3)²=25(x-2)² 2. (1+√2)x²-(1-√2)x=0

Answer 1

1.4(x+3)²=25(x-2)²

4(x+3)²-25(x-2)²=0

[2(X+3)+5(X-2)][2(X+3)-5(X-2)] =0

[2X+6+5X-10][2X+6-5X+10]=0

(7X-4)(-3X+16)=0

X=4/7或X=16/3；

2.(1+√2)x²-(1-√2)x=0

x[(1+√2)x-(1-√2)]=0

X=0或

X=(1-√2)/(1+√2)

=(1-√2)²/（1-2）

=-(1-√2)²

=-3+2√2

X=0或X=-3+2√2