Question

若当x=2时,ax5次方+bx3次方+cx-5的值是13.求当x=-2时,ax5次方+bx3次方+cx-5值

Answer 1

当x=2时,ax^5+bx^3+cx-5=a2^5+b2^3+2c-5=13

a2^5+b2^3+2c=18

当x=-2时,ax^5+bx^3+cx-5=-a2^5-b2^3-2c-5=-(a2^5+b2^3+2c)-5=-18-5=-23