Question

若x的三次方=-8,|y|=3,且（m-2)的二次方+(n+1)=0,求(x+y-n)的m次方.

Answer 1

x^3=-8====>x=-2

|y|=3====>y=+/-3

(m-2)^2+(n+1)^2=0=====>m=2,n=-1

(1):(x+y-n)^m=(-2+3+1)^2=4

(2):(x+y-n)^m=(-2-3+1)^2=16

不懂再问.