Question

函数与集合的几道题.1、（2又7/9）^1/2 + (0.1)^-2 + (2又10/27)^2/3 - 3π^0 +

Answer 1

1、（25/9）^1/2 + 1/[(0.1)^2] + (64/27)^2/3 - 3×1 +37/48

=5/3 +100 + (4/3)^2 -3 + 37/48 = 97 + 5/3 +16/9 =97 + 61/9

2、1/[(0.064)^1/3] +1 + (-2)^4 - 1/(16^3/4) +0.1

=1/0.4 +1 +16 - 1/8 +0.1= 17 +2.5 +0.1 -0.125

=19.475