化简(1-√3tanθ)sec(θ+π/3)cos

2个回答

(1-√3tanθ)sec(θ+π/3)cosθ
=2*(1/2*cosθ-√3/2sinθ)/cosθ/cos(θ+π/3)*cosθ
=2(cos(π/3)cosθ-sin(π/3)sinθ)/cos(θ+π/3)
=2cos(θ+π/3)/cos(θ+π/3)
=2

化简sin(θ-π)cos(θ-3/2π)cot(-θ-π)/tan(θ+3π)sec(-θ-2π)csc(π/2-θ)
化简：cot(θ+4π)•cos(θ+π)•sin2(θ+3π)tan(π+θ)•cos3(−π−θ)．
化简sin(θ−5π)tan(3π−θ)•1tan(θ−3π2)tan(π2−θ)•cos(8π−θ)sin(−θ−4π
化简 sin(θ-5π)•cot( π 2 -θ)•cos(8π-θ) tan(3π-θ)•tan(θ- 3 2 π)•
化简sin(θ-5π)•cot(π2-θ)•cos(8π-θ)tan(3π-θ)•tan(θ-32π)•sin(-θ-4
化简cosθ+cos(θ+2π/3)+cos(θ+4π/3)
化简[(tanθ*sinθ)/(tanθ-1)] +[ cosθ/(1-tanθ) ]
tan(π/6 -θ )+tan(π/6+θ)+根号3tan(π/6-θ)tan(π/6+θ)化简这个式子,
（tanθ-1）/(sinθ-cosθ)=secθ
化简sinθ(1+tanθ)+cosθ(1+cotθ)