Question

常温下,将20g 14%的nacl溶液跟30克24%.

Answer 1

1、m(NaCl)=20*14%+30*24%=10g n=10/(23+35.5)=0.206mol

V=m/密度＝(20+30)/1.15=43.48ml

量浓度c=n/V=0.206/43.48=0.0047mol/ml

2、设加入xmolNaCl.

x*(23+35.5)/(1000+x)=10/(20+30)

则x=4.14mol

加入4.14molNaCl.