Question

Y=根号下 x的平方+1加上根号下（4-x)的平方+4的最小值是?

Answer 1

y=sqrt(x^2+1)+Sqrt((4-x)^2)+4

y1=sqrt(x^2+1) ,y2=Sqrt((4-x)^2)

Min(y1)时,X=0,Min(y1)=1,Y2＝4,Y＝9

Min(y2)时,X=4,Min(y2)=0,Y1＝5,Y＝9

所以,Min(Y)=9