Question

1.PH=2的盐酸,和PH=4的盐酸溶液等体积混合后,计算所得溶液的PH值.2.计算PH=11的Ba(OH)2溶液与PH

Answer 1

1、c(H+) = (0.01 + 0.0001) / 2 = 0.00505 mol·L-1

pH = -lgc(H+) = 2.3

2、pH = 11 的 Ba(OH)2 溶液 pOH = 14－11 = 3,

pH = 9 的 NaOH 溶液 pOH = 14－9 = 5

c(OH-) = (0.001 + 0.00001) / 2 = 0.000505 mol·L-1

pOH = -lgc(OH) = 3.3

pH = 14－pOH = 14－3.3 = 10.7

3、c(OH-) = (0.6－0.4) / 2 = 0.1 mol·L-1

pOH = -lgc(OH) = 1

pH = 14－1 = 13