问对人了```哈哈````我初二数学没下过98分```
由3x+2y+z=5得:
z=5-3x-2y
将z=5-3x-2y带入2x+y-3z=1得:
2x+y-3(5-3x-2y)=1
即2x+y-15+9x+6y=1
11x=16-7y
x=16-7y/11
同理得y=16-11x/7
(/相当于分号)
其他两题没时间教你喇
睡觉去了``
x、y、z满足3x+2y+z=5,2x+y-3z=1.
2个回答
相关问题
-
x-5y-3z=0 y+z-3x=3 x+y+3z=14 y+4z=3 z+x-3y=5 2x+y+z=7 2x-z=1
-
x,y,z满足x+y+z=3,x^2+y^2+z^2=29,x^3+y^3+z^3=45,求x,y,z,x^4+y^4+
-
已知x，y，z满足[2/x＝3y−z＝5z+x]，求[5x−y/y+2z]的值．
-
已知x，y，z满足[2/x＝3y−z＝5z+x]，求[5x−y/y+2z]的值．
-
x+y+z=2 ① 2x+3y+z=38 ① x+y=3 3x-y-4z=5 ② 3x+4y+2z+56 ② y+z=5
-
证明：（y+z-2x）3+（z+x-2y）3+（x+y-2z）3=3（y+z-2x）（z+x-2y）（x+y-2z）．
-
(2X-3Y+Z)-3{X-2[-Z+(X-Y)]-(3Y-5Z)}
-
x-y+z=5 2x+3y+z=-2 x-2y-z=3
-
解三元一次方程组1)2x+y-3z=3,3x-y+2z=1,x-y-z=5 2)x:y=3:2,y:z=5:4,x+y+
-
⑴已知有理数x、y、Z满足x+y/3=y+z/4=z+x/5，且x+y+z=l2，则x= ___，y=___，z=___