Question

（x+y/x三分之一次方+Y三分之一次方）－（x三分之四方－y三分之四次方/x三分之二次方－y三分之二次方）

Answer 1

原式=[x^(1/3)+y^(1/3)][x^(2/3)-x^(1/3)y^(1/3)+y^(2/3)]/[x^(1/3)+y^(1/3)]-[x^(2/3)+y^(2/3)][x^(2/3)-y^(2/3)]/[x^(2/3)-y^(2/3)]

=x^(2/3)-x^(1/3)y^(1/3)+y^(2/3)-[x^(2/3)+y^(2/3)]

=-x^(1/3)y^(1/3)