Question

不定积分xsin(2+x^2)dx和(x-1)(x^2-2x+3)^10dx怎么解?

Answer 1

∫xsin(2+x^2)dx

=1/2∫sin(2+x^2)d(2+x^2)

=-1/2cos(2+x^2)+C

∫(x-1)(x^2-2x+3)^10dx

=1/2∫(x^2-2x+3)^10d(x^2-2x+3)

=1/22*(x^2-2x+3)^11+C