Question

解下列方程;(1)2/x+3=1/x-1 (2)1/x+1+3/2-x=0 (3)2/x+3+3/2=7/2(x+3)

Answer 1

(1)2/(x+3)=1/(x-1)

2x-2=x+3

x=5

(2)1/(x+1)+3/(2-x)=0

(2-x)+3(x+1)=0

2x+5=0

x=-5/2

(3)2/(x+3)+3/2=7/2(x+3)

4+3(x+3)=7

3x+6=0

x=-2

(4)2x/(2x-1)+x/(x-2)=2

2x(x-2)+x(2x-1)=2(2x-1)(x-2)

2x²-4x+2x²-x=4x²-10x+4

-4x-x+10x=4

x=4/5