x∈[0,π/12]
那么2x+π/6∈[π/6,π/3]
令2x+π/6=t∈[π/6,π/3]
f(x)=2sin(2x+π/6)=2sint
函数2sint,t∈[π/6,π/3]
当t=π/6,最小值为1
当t=π/3,最大值为根号3
f(x)=2sin(2x+π/6).当x∈[0,π/12]求fx最值
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