Question

分别取质量为10克的Na,Al,Fe三种金属,投入含有1摩尔HCl的盐酸溶液中,产生的氢气质量比为多少?

Answer 1

2Na+2H+=H2+2Na+

2 1

10/23 X X=5/23mol

2Al+6H+=3H2+2Al3+

6 3

1 Y Y=0.5mol

Fe+2H+=H2+Fe2+

1 1

10/56 Z Z=5/28mol

X:Y:Z=140:322:115