In[23]:= Solve[{A + B + C1 == 0,
A (b + c) + B (a + c) + C1 (a + b) == 0,
A b c + B a c + C1 a b == 1},{A,B,C1}]
{{A -> -(1/((-a + b) (a - c))),B -> -(1/((a - b) (b - c))),
C1 -> -(1/((a - c) (-b + c)))}}
记得加空格,否则连写则认为是一个变量名.
mathematica解符号变量方程
In[23]:= Solve[{A + B + C1 == 0,
A (b + c) + B (a + c) + C1 (a + b) == 0,
A b c + B a c + C1 a b == 1},{A,B,C1}]
{{A -> -(1/((-a + b) (a - c))),B -> -(1/((a - b) (b - c))),
C1 -> -(1/((a - c) (-b + c)))}}
记得加空格,否则连写则认为是一个变量名.