1.将下列三角函数化为锐角三角函数

1个回答

  • tan3π/5= tan(π-2π/5)=-tan2π/5,

    tan100°21′=tan(180°-79°39′)=-tan79°39′

    tan31π/36= tan(π-5π/36)=-tan5π/36

    tan324°32′=tan(360°-35°28′)=-tan35°28′

    cos65π/6=cos(60+5)π/6=cos5π/6=cos(π-π/6)=-cosπ/6=负的2分之根号3

    sin(-31π/4)=sin(-32+1)π/4=sin(π/4)=2分之根号2

    cos(-1182°13′)=cos(-1080°-102°13′)=cos(-102°13′)=cos102°13′=cos(180°-77°47′)=-cos77°47′

    sin670°39′=sin720°-49°21′=-sin49°21′

    tan(-26π/3)=tan(-24-2)π/3=tan-2π/3=-tan2π/3=-tan(π-π/3)=tanπ/3=根号3

    tan580°21′=tan(720°-139°39′)=-tan(180°-40°21′)=tan40°21′