Question

函数及其图像要算式和答案.1.若f(t)=t^2+1及g(t)=2t,求下列各值.a)g(3)+f(0) b)f(1)-

Answer 1

(1)

(a)g(3)+f(0)=2*3+1=7

(b)f(1)-g(-1)=3-(-2)=5

(2)h(3)=3*3²+m=27+m=1

m=-26

(3)

(a)f(3)=3²+3a+2=3a+11=20

则：a=3

(b)因为a=3

所以：f(x)=x²+3x+2=6

x²+3x-4=0

(x-1)(x+4)=0

x=1或者x=-4

(4)

(a)g(-1)=(k-1)(-1-2)=3-3k=-1

则：k=4/3

(b)因为k=4/3

所以：g(x)=(x+4/3)(x-2)

那么：3g(4)+6g(-2)=3*(4+4/3)(4-2)+6(-2+4/3)(-2-2)=32+16=48

(5)

(a)f(2t)=2(2t)+3=4t+3

f(t+2)=2(t+2)+3=2t+7

(b)因为：f(2t)=1/2 f(t+2)-1

所以：4t+3=(1/2)*(2t+7)-1

t=-1/6