Question

在273K和1.01×105 Pa下,将1.0 dm3洁净干燥的空气缓慢通过CH3OCH3液体,在此过程中,液体损失0.

Answer 1

n(醇) = m(醇) / M(醇) = 0.0335g / 46g/mol = 7.28×10^-4 mol

V(醇) = n(醇)RT / P(总)

= 7.28×10^-4 mol × 8314.3 Pa·dm3·mol-1·K-1 × 273K / 1.01×10^5 Pa = 0.016dm3

V(总) = 1.0 dm3 + 0.016dm3 = 1.016dm3

P(醇) = n(醇)RT / P(总)

= 7.28×10^-4 mol × 8314.3 Pa·dm3·mol-1·K-1 × 273K / 1.016dm3 = 1.63×10^3 Pa