Question

方程2x^-（「3 +1）x+m=0的两根为sinθ,cosθ,θ∈（0,2∏）,求（1）sinθ/1-cotθ+cos

Answer 1

sinθ/(1-cotθ)+cosθ/(1-tanθ)

=sinθ+cosθ

=（√3 +1）/2

sinθ+cosθ=（√3 +1）/2

sinθcosθ=m/2

(sinθ+cosθ)^2=1+2sinθcosθ=1+m=1+√3/2

m=√3/2