已知,二次函数y=mx²2 +3(m-1/4)x+4(m<0)与x轴交于A.B两点(A在B的左边),与y轴交于

2个回答

  • 二次函数y=mx^2+(m-3)x-3(m>0)

    x1+x2=(3-m)/m.(x1+x2)^2=(9-6m+m^2)/m^2

    x1*x2=-3/m

    AB=x2-x1=4

    (x2-x1)^2=(x1+x2)^2-4x1*x2=(9-6m+m^2)/m^2+12/m=16

    9-6m+m^2+12m=16m^2

    15m^2-6m-9=0

    5m^2-2m-3=0

    (5m+3)(m-1)=0

    m1=1.y=x^2-2x-3=(x+1)(x-3)

    m2=-3/5.y=-3x^2/5-18x/5-3=-3/5*(x^2+6x+5)=-3/5*(x-1)(x-5)

    C(0,-3)

    A1(-1,0)

    B1(3,0)

    A2(1,0)

    B2(5,0)

    圆M1圆心(1,-1),半径√5

    圆M2圆心(3,7/3),半径√85/3

    面积自己求吧