是x∈[0,π/2]吧?则2x＋π/3∈[π/3,4π/3],则本题相当于求函数y=sinx,其中x∈[π/3,4π/3]时的值域,利用函数图像,得y∈[－1,1/2].
y=cos(2x+π/3)在{0.π/2}的值域
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